Sunday, 18 September 2016

StringBuffer object by literal

in: StringBuffer by literal

13.3 literal

Can we create StringBuffer object by literal?

It is not possible to create StingBuffer object by using literal
Even if we try to create we will get compile time error.
So, creating StringBuffer object by using literal means its literally invalid

Invalid Syntax

StringBuffer stringBuffer = "Java"; // Invalid

Thanks for your time.

Nireekshan